Check out the problem description here. Maximum Width of Binary Tree - LeetCode Given the root of a binary tree, return the maximum width of the given tree. The maximum width of a tree is the maximum…leetcode.com Approach 1: Traverse level by level. Store all the nodes in the level , including the null values. For each level find left most and right most non null nodes and find the maximum width Time limit exceeded.

Check out the problem description here. Lowest Common Ancestor of a Binary Tree - LeetCode Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree. According to the definition…leetcode.com Solution Approach 1: Store both the paths to p and q , in to 2 arrays , by traversing the tree . And finally compare the array elements to see the common ancestor. The LCA will be the last common element in both array…

Check out the problem description here. Binary Tree Paths - LeetCode Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared…leetcode.com class Solution: def binaryTreePaths(self, root: Optional[TreeNode]) -> List[str]: res=[] ds=[] self.rec(root,res,ds)…

Check out the problem description here. Path to Given Node - InterviewBit Path to Given Node - Problem Description Given a Binary Tree A containing N nodes. You need to find the path from Root…www.interviewbit.com Solution class Solution: def solve(self, A, B): ds=[] self.rec(A,B,ds) return ds def rec(self,root,B,ds): if root ==None : return False ds.append(root.val) if root.val == B: return True if self.rec(root.left,B,ds) or self.rec(root.right,B,ds): return True ds.pop(-1) return False

Check the problem description here Symmetric Tree - LeetCode Given the root of a binary tree, check whether it is a mirror of itself (i.e., symmetric around its center). Example 1…leetcode.com Solution Recursive solution Recursively check if the mirror nodes are same. class Solution: def isSymmetric(self, root: Optional[TreeNode]) -> bool: if root: return self.helper(root.left,root.right)…

Check out the problem description here. Binary Tree Right Side View - LeetCode Given the root of a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you…leetcode.com Solution Approach 1 Iterative using level order traversal. You can use level order traversal, with traversing from a)left to right -here the last node in each level is what contribute to the right view

Check out the problem description here https://www.codingninjas.com/codestudio/problems/893110?topList=striver-sde-sheet-problems&utm_source=striver&utm_medium=website&leftPanelTab=1 Solution Traverse level order, and pushing the nodes to queue with the node and its x coordinate(position of imaginary vertical line ) .While popping the node from queue keep updating the imaginary vertical line with latest value popped from the queue and which…

Check out the problem description here. Top View Of Binary Tree for coding interview round As we know that all three traversals, i.e. pre-order, in-order and post-order, visit the tree node at once. We can use…www.codingninjas.com Solution Traverse level order, and pushing the nodes to queue with the node and its x coordinate(position of imaginary vertical line ) .While popping the node from queue store the first node value for each imaginary vertical line in to a dictionary .Finally return…

Given a binary tree, return the values of its boundary in anti-clockwise direction starting from root. Boundary includes left boundary, leaves, and right boundary in order without duplicate nodes. Left boundary is defined as the path from root to the left-most node. Right boundary is defined as the path from…